4a^2-4a-63=0

Solution for 4a^2-4a-63=0 equation:

4a^2-4a-63=0

a = 4; b = -4; c = -63;
Δ = b2-4ac
Δ = -42-4·4·(-63)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-32}{2*4}=\frac{-28}{8}
=-3+1/2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+32}{2*4}=\frac{36}{8}
=4+1/2
$